Question

How do you simplify `(16x ^ { 8} y ^ { 6} ) ^ { 1/ 2}`?

Answer 1

`4x^4y^3`

Explanation:

`x^(a/b) = root(b)(x^a)`

`(16x^8y^6)^(1/2) = root(2)((16x^8y^6)^1) = sqrt(16x^8y^6) = 4x^4y^3`