Question #201b5

1 Answer
Aug 1, 2017

#0.538# #"g"# #""^13"C"#

Explanation:

We're asked to find the number of moles of #""^13"C"# that has a mass of #7.00# #"g"#.

Carbon-13 is merely an isotope of carbon, and its isotopic mass is #13.003# #"amu"# (from a source), which means its molar mass is #13.003# #"g/mol"#.

Thus, we use this molar mass when performing our conversion from mass to moles:

#7.00cancel("g"color(white)(l)""^13"C")((1color(white)(l)"mol"color(white)(l)""^13"C")/(13.003cancel("g"color(white)(l)""^13"C"))) = color(red)(ul(0.538color(white)(l)"mol"color(white)(l)""^13"C"#