What is the value of the expression #2/3(6-5/6)#?

1 Answer
Aug 1, 2017

See a solution process below:

Explanation:

First, we want to subtract the numbers within the parenthesis. However, to do this we must put each number over a common denominator. We can do his by multiplying #6# by the appropriate for of #1#:

#2/3(6 - 5/6) =>#

#2/3([6/6 xx 6] - 5/6) =>#

#2/3(36/6 - 5/6) =>#

#2/3(31/6)#

Next, we can multiply the two fractions to complete the evaluation of the expression:

#2/3(31/6) =>#

#2/3 xx 31/6 =>#

#(2 xx 31)/(3 xx 6) =>#

#62/18#

Now, we can factor the numerator and denominator so we can cancel common terms. This will give the simplest form of the fraction:

#(2 xx 31)/(2 xx 9) =>#

#(color(red)(cancel(color(black)(2))) xx 31)/(color(red)(cancel(color(black)(2))) xx 9) =>#

#31/9#