Question

How do you plot two points that lie along the boundary line for the inequality `y>2x+1`?

Answer 1

Refer to the explanation for the process.

Explanation:

Given:

`y>3x+1`

Make the two points the x-intercept and the y-intercept.

X-Intercept

The x-intercept is the value of `x` when `y=0`.

`0>3x+1`

Subtract `3x` from both sides.

`-3x>1`

Divide both sides by `-3`. This will reverse the inequality.

`x<-1/3`

Point: `(-1/3,0)`

Y-Intercept

The y-intercept is the value of `y` when `x=0`.

`y>3(0)+1`

`y>1`

Point: `(0,1)`

Plot the points and draw a straight dashed line through them to show that the line is the boundary of the inequality, but is not included in the inequality. Then shade the area above the line to represent the inequality.

graph{y>3x+1 [-10, 10, -5, 5]}