How do you simplify #\frac { ( w - 2) ^ { 2} } { w + 2} \cdot \frac { 1} { w - 2}#?

1 Answer
seol
Aug 2, 2017

#(w-2)/(w+2)#

Explanation:

If you have factors that are equivalent in the numerator and denominator, you can cancel them.

Example: #(xbc)/(xdf)#, you see there is an #x# in the numerator and denominator. You can cancel them out together to get #(bc)/(df)#.

#(w-2)^2/(w+2)\cdot1/(w-2)#
#((w-2)(w-2))/(w+2)\cdot1/(w-2)# Expanded square
#(\cancel((w-2))(w-2))/(w+2)\cdot1/\cancel((w-2))# Cancel equivalent factors
#(w-2)/(w+2)\cdot1/1# Simplified. Since 1 has no effect on the value, the answer is #(w-2)/(w+2)#

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