How does #sec^2(pi/2-theta)+csc^2(pi/2-theta)=sec^2thetacsc^2theta#?
This is the original question.
Show: #sec^2(pi/2-theta)+csc^2(pi/2-theta)=sec^2thetacsc^2theta#
This is the first part of the answer that my answer book gives me.
#sec^2(pi/2-theta)+csc^2(pi/2-theta)=sec^2thetacsc^2theta#
I don't see how #sec^2(pi/2-theta)+csc^2(pi/2-theta)# is equal to #sec^2thetacsc^2theta# .
This is the original question.
Show:
This is the first part of the answer that my answer book gives me.
I don't see how
1 Answer
Aug 2, 2017