How do you solve the system of equations #8x + 3y = - 4# and #5x + 2y = 6#?

1 Answer

#(x,y)=(-26,68)#

Explanation:

I'll solve this by first eliminating the #y# terms in both equations:

#E1: 8x+3y=-4=>16x+6y=-color(white)(1)8#
#E2: 5x+2y=color(white)(-)6=>ul(15x+6y=color(white)(-)18#
#E1-E2: color(white)(8x+3y=0.00)x+0y=-26#

#:. color(blue)(x=-26)#

Substitute back into one one of the original equations:

#E1: 8(-26)+3y=-4#

#E1: -208+3y=-4#

#E1: 3y=204=>color(blue)(y=68)#

Let's check our answer via graphing (because the lines are so close to being parallel, I've had to really focus the graph):

graph{(8x+3y+4)(5x+2y-6)=0[-27,-25,66,70]}