How do you solve #20- 10\leq x + 5#?

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Answer 1 · 2017-08-02T13:07:48

#x>=5#

First, do the calcul "20-10"

#10<=x+5#

Then, change "x" and "10" side and do not forget to change the sign, so it gives us

#-x<=5-10#

Calcul "5-10"

#-x<=-5#

Then, take off the sign "-" to the number five and "x" and DO NOT forget to change #<=# to #>=#

#x>=5#