How do you solve #8( x + 4) + 3( - 4x ) = 32#?

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Answer 1 · 2017-08-02T18:01:04

The solution is #x=0#.

We start with:

#8(x+4)+3(−4x)=32#

First expand the brackets:

#8x+32−12x=32#

Subtract 32 from each side:

#8x-12x=0#

#-4x=0#

#x=0/(-4)=0#