How do you order these from smallest to largest: #sqrt(9/25), 2/3, 62% and .66#?

1 Answer
Aug 3, 2017

Convert all values into a form that you can manage with. Order accordingly.

Explanation:

The easiest way to do this is to evaluate them into a form that is easy to manage. In my opinion, I believe decimals are easy to work with, so we're going to convert all these values into decimals.

The first one: #sqrt(9/25)#.

To do this, we just simplify the fraction. #9# and #25# are both squared numbers, so if we find the square root of these values and divide, then we have our decimal!

#(sqrt9/25)#

#=3/5#

I'm actually going to convert this into tenths but it's not necessary.

#=6/10#

#=0.6#

The second one: #2/3#.

We know that #2/3# are simply #0.667#. We can check our work by inserting it into a calculator.

The third one: #65%#.

Percents are just essentially a decimal itself, where #100%# is #1# #"whole"#. Thus, #65%# is equal to #0.65#.

The last one: #0.66#.

It's already a decimal so no need to do anything.

With all decimal values: #0.6,0.667, 0.65, #and #0.66#.

We can easily order them from smallest to largest.

Thus, we get: #0.6, 0.65, 0.66# and finally #0.667#.

Hope this helps :)