Question

Angie Applegate has a photograph for which the length is 2 inches longer than the width. If she increases each dimension by 4 inches, the area is increased by 88 square inches. How do you find the original dimensions?

Answer 1

`8"in" xx 10"in"`

Explanation:

At first you have `x(x+2)=a`, and after, you have `(x+4)(x+6)=a+88`

By expanding the brackets you get `x^2+10x+24=a+88`

By putting all terms onto one side, you get `x^2+10x-64=a`

`x^2+10x-64=a`
`x^2+2x=a`

`x^2+10x-64=x^2+2x`

`8x-64=0`

`8x=64`

`x=64/8=8`

`8(8+2)=8*10=80`
`(8+4)(8+6)=12*14=168`
`168-80=88`

`x=8"in"`
`x+2=8+2=10"in"`

`8"in" xx 10"in"`