How do you evaluate #sin 25 cos 65 + cos 25 sin 65#?
1 Answer
Aug 3, 2017
Explanation:
#"using the "color(blue)"trigonometric identity"#
#•color(white)(x)sin(A+B)=sinAcosB+cosAsinB#
#"here " A=25" and "B=65#
#rArrsin(25+65)^@#
#=sin90^@#
#=1#
