Question

The position of an object moving along a line is given by `p(t) = 2t^3 - 5t^2 +2`. What is the speed of the object at `t = 2`?

Answer 1

I got `4m/s`

Explanation:

We can derive our position function to find the average velocity and then evaluate it a our instant to get the instantaneous one.
We get:

`v(t)=(dp(t))/dt=6t^2-10t`

at `t=2`

`v(2)=6*4-10*2=24-20=4m/s`