Determine an equation for the tangent line to the graph of #f(x)=(2x+1)^2+ln(4x-3)# at the point #x=1#?
Please do not skip any steps!
Please do not skip any steps!
1 Answer
Aug 5, 2017
The equation is
Explanation:
We need
Our function is
We calculate the first derivative
The equation of the tangent is
Here
Therefore, the equation is
graph{(y-(2x+1)^2-ln(4x-3))(y-16x+7)=0 [-32.2, 8.35, 1.1, 21.38]}