How do you find the magnitude of #<5,6># and write it as a sum of the unit vectors?

1 Answer
Aug 5, 2017

#"magnitude" = 7.810#

#< 5,6 > = 5hati + 6hatj#

Explanation:

We'll call the given vector #vecA# with components #A_x = 5# and #A_y = 6#.

The magnitude of a vector is given by

#|vecA| = sqrt((A_x)^2 + (A_y)^2) = sqrt(5^2 + 6^2) = color(blue)(ulbar(|stackrel(" ")(" "7.810" ")|)#

#" "#

Vectors in the notation #< x,y ># can also be represented by unit vectors, with the unit vector #hati# for the #x#-component and #hatj# for the #y#-component:

#< 5,6 > = color(blue)(ulbar(|stackrel(" ")(" "5hati + 6hatj" ")|)#