How high a column of air would be necessary to cause the barometer to read 76 cm of Hg, if the atmosphere were of uniform density #1.2Kg/m^3#? The density of Hg = #13.6*10^3Kg/m^3#

Question

A: 8613 m
B: 8613 cm
C: 8.613 m
D: 8613 mm

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Answer 1 · 2017-08-06T14:23:07

The height is option #(A)=8613m#

#p=rho g h#

The density is #rhokgm^-3#

The height is #hm#

and #g=9.8ms^-2#

Height of the column of air is #h_(air)#

Height of the column of mercury is #h_(Hg)#

Therefore,

#rho_(air)gh_(air)=rho_(Hg) gh_(Hg)#

#h_(air)=(rho_(Hg) h_(Hg))/(rho_(air))=(13.6*10^3*0.76)/1.2=8613m#