How high a column of air would be necessary to cause the barometer to read 76 cm of Hg, if the atmosphere were of uniform density 1.2Kg/m^3? The density of Hg = 13.6*10^3Kg/m^3

A: 8613 m
B: 8613 cm
C: 8.613 m
D: 8613 mm

1 Answer
Aug 6, 2017

The height is option (A)=8613m

Explanation:

The pressure is

p=rho g h

The density is rhokgm^-3

The height is hm

and g=9.8ms^-2

Height of the column of air is h_(air)

Height of the column of mercury is h_(Hg)

Therefore,

rho_(air)gh_(air)=rho_(Hg) gh_(Hg)

h_(air)=(rho_(Hg) h_(Hg))/(rho_(air))=(13.6*10^3*0.76)/1.2=8613m