How do you solve #7x^2-5=0#?

1 Answer
Aug 7, 2017

See a solution process below:

Explanation:

First, add #color(red)(5)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#7x^2 - 5 + color(red)(5) = 0 + color(red)(5)#

#7x^2 - 0 = 5#

#7x^2 = 5#

Next, divide both sides of the equation by #color(red)(7)# to isolate #x^2# while keeping the equation balanced:

#(7x^2)/color(red)(7) = 5/color(red)(7)#

#(color(red)(cancel(color(black)(7)))x^2)/cancel(color(red)(7)) = 5/7#

#x^2 = 5/7#

Now, take the square root of each side of the equation to solve for #x# while keeping the equation balanced. Remember, taking the square root of a number produces both a positive and negative result:

#sqrt(x^2) = +-sqrt(5/7)#

#x = +-sqrt(5/7)#