How do you multiply #(7-6i)(-8 +3i)#?
1 Answer
Aug 7, 2017
Explanation:
#"multiply out using FOIL"#
#=-56+21i+48i-18i^2#
#[i^2=(sqrt(-1))^2=-1]#
#=-56+69i+18#
#=-38+69ilarrcolor(red)" in standard form"#
