How do you solve #\frac { 3n } { 2} = \frac { - 9} { 10}#?

1 Answer
Aug 9, 2017

See a solution process below:

Explanation:

Multiply each side of the equation by #color(red)(2)/color(blue)(3)# to solve for #n# while keeping the equation balanced:

#color(red)(2)/color(blue)(3) xx (3n)/2 = color(red)(2)/color(blue)(3) xx (-9)/10#

#cancel(color(red)(2))/cancel(color(blue)(3)) xx (color(blue)(cancel(color(black)(3)))n)/color(red)(cancel(color(black)(2))) = (color(red)(2) xx -9)/(color(blue)(3) xx 10)#

#n = (-18)/30#

#n = -(6 xx 3)/(6 xx 5)#

#n = -(color(red)(cancel(color(black)(6))) xx 3)/(color(red)(cancel(color(black)(6))) xx 5)#

#n = -3/5#