How do you solve #7(6-3k)=147#?

3 Answers
Aug 9, 2017

See a solution process below:

Explanation:

Step 1) Divide each side of the equation by #color(red)(7)# to eliminate the need for the parenthesis while keeping the equation balanced:

#(7(6 - 3k))/color(red)(7) = 147/color(red)(7)#

#(color(red)(cancel(color(black)(7)))(6 - 3k))/cancel(color(red)(7)) = 21#

#6 - 3k = 21#

Step 2) Subtract #color(red)(6)# from each side of the equation to isolate the #k# term while keeping the equation balanced:

#-color(red)(6) + 6 - 3k = -color(red)(6) + 21#

#0 - 3k = 15#

#-3k = 15#

Step 3) Divide each side of the equation by #color(red)(-3)# to solve for #k# while keeping the equation balanced:

#(-3k)/color(red)(-3) = 15/color(red)(-3)#

#(color(red)(cancel(color(black)(-3)))k)/cancel(color(red)(-3)) = -5#

#k = -5#

Aug 9, 2017

See below

#k=-5#

Explanation:

To solve #7(6−3k)=147#, first divide both sides by 7

#7(6−3k)-:7=147/7" "rArr" "6−3k=21#

next subtract 6 from both sides#" "6−3k-6=21-6#

#rArr" "-3k=15#

now divide both sides by #-3" "-3k/-3=15/-3" "rArr k=-5#

Aug 9, 2017

#k=-5#

Refer to the explanation for the process.

Explanation:

Solve:

#7(6-3k)=147#

Expand using the distributive property: #a(b+c)=ab+bc#.

#42-21k=147#

Subtract #42# from both sides.

#-21k=147-42#

Simplify.

#-21k=105#

Divide both sides by #-21#.

#k=105/(-21)#

Simplify.

#k=-5#