How do you graph the equation #y=-3/4x-1#?

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Answer 1 · 2017-08-09T10:30:56

See a solution process below:

First, calculate two points from the equation and plot them on the graph:

For #x = 0#:

#y = (-3/4 * 0) - 1#

#y = 0 - 1#

#y = -1# or #(0, -1)#

For #x = 4#

#y = (-3/4 xx 4) - 1#

#y = -3 - 1#

#y = -4# or #(4, -4)#

graph{(x^2 + (y+1)^2 - 0.125)((x-4)^2+(y+4)^2-0.125)=0 [-20, 20, -10, 10]}

Now, draw a line through the two points:

graph{(y + ((3/4)x)+1)(x^2 + (y+1)^2 - 0.125)((x-4)^2+(y+4)^2-0.125)=0 [-20, 20, -10, 10]}