Question

A `2.19*g` mass of potassium nitrate is dissolved in a `75*g` mass of water. What is it percentage concentration?

Answer 1

`"% by mass"="mass of solute"/"mass of solute + solvent"xx100%~=3%`

Explanation:

`"% by mass"=(2.19*g)/(2.19*g+75*g)xx100%=?%`

The volume of this solution would not be much different to the volume of the starting solution. And the likely solvent is water.....