Question

A closed organ pipe is 25 cm long. The velocity of sound in air is 330 ms^-1. How do you calculate the frequency of the fundamental vibratory mode?

Answer 1

`f=330"Hz"`

Explanation:

The fundamental frequency produced by a closed pipe of length `L` is given by the equation:

`f=v/(4L)`

where `v` is the speed of sound.

Given `v=330"m"//"s"`

`f=(330"m"//"s")/(4*0.25"m")`

`=330"Hz"`

Here is a good, concise description of open and closed pipes and an explanation of the above equation from another Socratic user.