Question

Can someone please help me with this question,the answer I got was wrong which is this one (4q+3)^2/16. Here is the question? (q+3/4)(q+3/4)

Answer 1

I think the Question demands the Expansion, which is,

`(q^2+3/2*q+9/16)=1/16(16q^2+24q+9).`

Answer 2

see picture

Explanation:

Answer 3

Your answer looks correct to me, but perhaps the expected form was:
`color(white)("XXX")q^2+3/2q+9/16`

Explanation:

`(q+3/4)(q+3/4)`

`color(white)("XXX")=q(q+3/4)color(white)("xx")+color(white)("xx")3/4(q+3/4)`

`color(white)("XXX")=q^2+3/4qcolor(white)("xx")+color(white)("xx")3/4q+9/16`

`color(white)("XXX")=q^2+6/4q+9/16`

`color(white)("XXX")=q^2+3/2q+9/16`

However, your answer:
`(4q+3)^2/16`

`color(white)("XXX")=(16q^2+24q+9)/16`

`color(white)("XXX")=(16q^2)/16+(24q)/16+9/16`

`color(white)("XXX")=q^2+3/2q+9/16`

So the results are equivalent.

Answer 4

`"see explanation"`

Explanation:

`"expand "(q+3/4)(q+3/4)" using FOIL"`

`=q^2+3/4q+3/4q+(3/4xx3/4)`

`=q^2+3/2q+9/16`

`"now express each term as a fraction in "1/16's`

`"that is "(q^2xx16/16)+(3/4qxx4/4)+9/16`

`=(16q^2+12q+9)/16`

`"the numerator is a perfect square "(4q+3)^2`

`rArr(q+3/4)(q+3/4)=(4q+3)^2/16`