How do you solve #41= 12d - 7 #?

1 Answer
Anthony R.
Aug 13, 2017

#d=4#

Explanation:

Add #7# from both sides

#41color(red)(+7)=12dcancel(-7color(red)(+7))#

#48=12d#

Divide #12# from both sides to isolate the variable and solve for #d#

#48/color(red)12=cancel12/cancelcolor(red)12d#

#4=d#

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