Y={√x+1/√x}² Find the dy/dx for this function?

1 Answer
Aug 13, 2017

=2(sqrtx +1/sqrtx)(1/(2sqrtx) -1/(2x^(3/2)) )

Explanation:

(dY)/dx= d/dx (sqrtx +1/sqrtx)^2= 2(sqrtx +1/sqrtx) d/dx (sqrtx+ 1/sqrtx)

=2(sqrtx +1/sqrtx)(1/(2sqrtx) -1/(2x^(3/2)) )