Question

Y={√x+1/√x}² Find the dy/dx for this function?

Answer 1

`=2(sqrtx +1/sqrtx)(1/(2sqrtx) -1/(2x^(3/2)) )`

Explanation:

`(dY)/dx= d/dx (sqrtx +1/sqrtx)^2= 2(sqrtx +1/sqrtx) d/dx (sqrtx+ 1/sqrtx)`

`=2(sqrtx +1/sqrtx)(1/(2sqrtx) -1/(2x^(3/2)) )`