How do you solve $4 x + 2 y - 2 = 30 ?$ $4x+2y -2=30?$

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Answer 1 · 2017-08-14T15:31:12

There are two variables and only one equation. With only one equation there are an infinite number of points that would fall on the line.

The equation can be simplified and put into the form $y = m x + b$ $y = mx + b$

$4 x + 2 y - 2 = 30$ $4x + 2y -2 = 30$

$4 x - 4 x + 2 y - 2 + 2 = - 4 x + 30 + 2$ $4x -4x + 2y - 2 + 2 = -4x + 30 +2" "$ This gives

$2 y = - 4 x + 32$ $2y = -4x + 32" "$ dividing everything by $2$ $2$ gives..

$\frac{2 y}{2} = \frac{- 4 x}{2} + \frac{32}{2}$ $(2y)/2 = (-4x)/2 + 32/2" "$ which equals

$y = - 2 x + 16$ $y = -2x + 16" "$ Put in any value for $x$ $x$ and solve for $y$ $y$

Such as $x = 1$ $x = 1$

$y = - 2 \times 1 + 16$ $y = -2xx1 + 16$

$y = 14 .$ $y = 14.$

To find unique values for $x and y$ $x and y$ it is necessary to have two equations, because there are two variables.

How do you solve 4x+2y−2=30?4x+2y -2=30?