Question

How do you differentiate `g(y) =x^2(x^2 - 1)` using the product rule?

Answer 1

`g'(x)=4x^3-2x`

Explanation:

`g(x)=x^2(x^2-1)`
Differentiating Both sides with respect to `x` we get
`g'(x)=2x (x^2-1)+x^2×2x`
`:.g'(x)=4x^3-2x`