If cos theta =7/8,evaluate{(1+sin theta)(1-sin theta)]/[(1+cos theta)(1-cos theta)] ?

1 Answer
Aug 17, 2017

{(1+sin theta)(1-sin theta)]/[(1+cos theta)(1-cos theta)]

=(1-sin^2theta)/(1-cos^2theta)

=(cos^2theta)/(1-cos^2theta)

=(7/8)^2/(1-(7/8)^2)

=(7/8)^2/((8^2-7^2)/8^2)

=49/15