A 20 cm wire carrying a current of 0.545A feels a 650 N force. What is the strength of the magnetic field?

1 Answer
Aug 18, 2017

B=5963.3T

Explanation:

We know that the force on a current carrying wire in a magnetic field is given by

F=ILB

Where
F: Force experienced by the wire.
I: Current in the wire.
L: Length of the wire.
B: Magnetic field.

In our case it is given that
F=650N
I=0.545A
L=20cm=0.2m
:.650=0.545×0.2×B
:.B=5963.3T