Question

A 20 cm wire carrying a current of 0.545A feels a 650 N force. What is the strength of the magnetic field?

Answer 1

`B=5963.3T`

Explanation:

We know that the force on a current carrying wire in a magnetic field is given by

`F=ILB`

Where
`F:` Force experienced by the wire.
`I:` Current in the wire.
`L:` Length of the wire.
`B:` Magnetic field.

In our case it is given that
`F=650N`
`I=0.545A`
`L=20cm=0.2m`
`:.650=0.545×0.2×B`
`:.B=5963.3T`