How do you solve #-5x - 5\frac { 1} { 4} = - 16\frac { 3} { 4}#?

2 Answers
Aug 18, 2017

#x = 2 3/10#

Explanation:

#-5x-5 1/4 = -16 3/4" "larr# re-arrange the equation

#16 3/4 -5 1/4 = 5x" "larr# simplify the fractions

#11 1/2 = 5x#

#23/2 =5x" "larr div 5# on both sides

#23/(2xx5) = (5x)/5#

#23/10 = x#

#x = 2 3/10#

Aug 18, 2017

See a solution process below:

Explanation:

First, convert the two mixed numbers to improper fractions:

#-5x - 5 1/4 = -16 3/4#

#-5x - (5 + 1/4) = -(16 + 3/4)#

#-5x - ([4/4 xx 5] + 1/4) = -([4/4 xx 16] + 3/4)#

#-5x - (20/4 + 1/4) = -([64/4 + 3/4)#

#-5x - (20 +1)/4 = -(64 + 3)/4#

#-5x - 21/4 = -67/4#

Next, add #color(red)(21/4)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#-5x - 21/4 + color(red)(21/4) = -67/4 + color(red)(21/4)#

#-5x - 0 = (-67 + color(red)(21))/4#

#-5x = -46/4#

#-5x = -(23 xx 2)/(2 xx 2)#

#-5x = -(23 xx color(red)(cancel(color(black)(2))))/(2 xx color(red)(cancel(color(black)(2))))#

#-5x = -23/2#

Then, multiply each side of the equation by #color(red)(-1/5)# to solve for #x# while keeping the equation balanced.

#-5x xx color(red)(-1/5) = -23/2 xx color(red)(-1/5)#

#-color(red)(cancel(color(black)(5)))x xx color(red)(-1/color(black)(cancel(color(red)(5)))) = 23/10#

#-x xx -1 = 23/10#

#x = 23/10#

If necessary, we can convert the result to a mixed number:

#x = (20 + 3)/10#

#x = 20/10 + 3/10#

#x = 2 + 3/10#

#x = 2 3/10#