How many electrons are found in a sample of dioxygen gas contained in a $0.448 L$ $"0.448 L"$ container at STP?

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How many electrons are found in a sample of dioxygen gas contained in a $0.448 L$ $"0.448 L"$ container at STP?

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Answer 1 · 2017-08-19T06:15:33

$1.20$ $1.20$ x $10^{22}$ $10^22$ electrons

Explanation:

The no of electrons present in448 ml of O2 at STP
At STP conditions 1 mole of O2 gas = $6.023$ $6.023$ x $10^{23}$ $10^23$ electrons

$1$ $1$ mole = $22.4$ $22.4$ L
So, $22.4$ $22.4$ L of $O_{2}$ $O_2$ = ( $6.023$ $6.023$ x $10^{23}$ $10^23$ electrons)
$0.448$ $0.448$ L of $O_{2}$ $O_2$ = ( $6.023$ $6.023$ x $10^{23}$ $10^23$ electrons)x ( $0.448$ $0.448$ )]/ $22.4$ $22.4$ L
= $1.20$ $1.20$ x $10^{22}$ $10^22$ electrons

Answer 2 · 2017-08-19T06:16:27

See.

Explanation:

$22400 m l$ $22400ml$ $O_{2}$ $O_2$ contains $16 \times N_{A}$ $16×N_A$ electrons
$1 m l$ $1ml$ $O_{2}$ $O_2$ contains $\frac{16 \times N_{A}}{22400}$ $(16×N_A)/22400$ electrons
Hence, $448 m l$ $448ml$ contains $\frac{16 \times N_{A} \times 448}{22400}$ $(16×N_A×448)/22400$ electrons= $0.32 \times N_{A}$ $0.32×N_A$
Here, $N_{A}$ $N_A$ is Avogadro number.

Answer 3 · 2017-08-19T16:14:31

About $1.93 \times 10^{23}$ $1.93 xx 10^23$ electrons.

Assuming your definition of STP is $0^{\circ} C$ $0^@ "C"$ and $1 atm$ $"1 atm"$ , the molar volume of $O_{2}$ $"O"_2$ , assuming it is an ideal gas, is based on the ideal gas law:

$P V = n R T$ $PV = nRT$

for pressure $P$ $P$ , volume $V$ $V$ , mols $n$ $n$ , temperature $T$ $T$ , and universal gas constant $R$ $R$ .

Rearranging, we get...

$\frac{V}{n} = \frac{R T}{P}$ $V/n = (RT)/P$

$= \frac{(0.082057 L \cdot atm/mol \cdot K) (273.15 K)}{1 atm}$ $= (("0.082057 L"cdot"atm/mol"cdot"K")("273.15 K"))/"1 atm"$

$=$ $=$ $22.414 L/mol$ $"22.414 L/mol"$

So, with this molar volume, we compare ratios:

$\frac{0.448 L}{x mols} = \frac{22.414 L}{mol}$ $"0.448 L"/("x mols") = "22.414 L"/"mol"$

$\Rightarrow n_{O_{2}} = 0.0200 mols$ $=> n_("O"_2) = "0.0200 mols"$

Each $O$ $"O"$ atom contains $8$ $8$ electrons, so each $O_{2}$ $"O"_2$ molecule contains... well, $16$ $16$ .

${0.0200 mols O}_{2} \leftrightarrow {0.320 mols e}^{-}$ $"0.0200 mols O"_2 harr "0.320 mols e"^(-)$

And thus, the number of electrons is given by

$Number of electrons = {0.320 mols e}^{-} \times 6.0221413 \times 10^{23} {mol}^{- 1}$ $color(blue)("Number of electrons") = "0.320 mols e"^(-) xx 6.0221413 xx 10^(23) "mol"^(-1)$

$= ulcolor(blue)(1.93 xx 10^(23)color(white)(.)"e"^(-))$

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How many electrons are found in a sample of dioxygen gas contained in a $0.448 L$ $"0.448 L"$ container at STP?

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How many electrons are found in a sample of dioxygen gas contained in a "0.448 L"0.448 L"0.448 L" container at STP?

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Explanation:

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How many electrons are found in a sample of dioxygen gas contained in a $0.448 L$ $"0.448 L"$ container at STP?