Question #f60e7

1 Answer
Sarthak
Aug 19, 2017

Absolute error in y = y multiplied by sum of fractional error in a and b

Explanation:

#y=a/b#
#rArr (Deltay)/y=(Deltaa)/a+(Deltab)/b#
#rArr Deltay=y((Deltaa)/a+(Deltab)/b)#

Where
#Deltay,Deltaa # and #Deltab#= absolute errors in y,a,b

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