How do you divide #(x ^ { 2} + 8x - 33) \div ( x - 5)#?
1 Answer
Aug 20, 2017
Explanation:
#"one way is to use the divisor as a factor in the numerator"#
#"consider the numerator"#
#color(red)(x)(x-5)color(magenta)(+5x)+8x-33#
#=color(red)(x)(x-5)color(red)(+13)(x-5)color(magenta)(+65)-33#
#=color(red)(x)(x-5)color(red)(+13)(x-5)+32#
#"quotient "=color(red)(x+13)," remainder "=32#
#rArr(x^2+8x-33)/(x-5)=x+13+32/(x-5)#
