How do you find a=1/3(2b-5c) given b=<6,3> and c=<-4,8>?
1 Answer
Aug 21, 2017
Explanation:
#ula=1/3(2ulb-5ulc)#
#color(white)(xx)=1/3[2((6),(3))-5((-4),(8))]#
#"multiply each component by the scalar quantity"#
#ula=1/3[((12),(6))+((20),(-40))]#
#"add corresponding components in each vector"#
#rArrula=1/3((32),(-34))=((32/3),(-34/3))#
