Question #31fd3

1 Answer
Aug 22, 2017

infinity

Explanation:

ln(x+1)=log_e"(x+1)

log_e"(x+1)=y

e^y=(x+1)

lim_"x-->oo" e^y=oo+1 (oo+1=oo)

(e^y=oo)

So, y should be infinity

y is the value of the limit..