Question #f6944

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Question #f6944

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Answer 1 · 2017-08-22T12:36:11

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Explanation:

$1 m o l$ $1mol$ oxygen contains $2 \times N_{A}$ $2×N_A$ molecules
→contained in $22.4 d m^{3}$ $22.4dm^3$ volume $O_{2}$ $O_2$
So,
$44.8 d m^{3}$ $44.8dm^3$ contains $4 \times N_{A}$ $4×N_A$ molecules = $4 \times 6.022 \times 10^{23} = 2.4088 \times 10^{24}$ $4×6.022×10^23=2.4088×10^24$

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