Question

What are the asymptotes and removable discontinuities, if any, of `f(x)= (2-2x)/(x-1)`?

Answer 1

`f(x)=-2xx(x-1)/(x-1)`

Explanation:

`x=1` would lead to an undefined answer (`-2xx0/0`)

For all other values:

`f(x)=-2xx(cancel(x-1))/(cancel(x-1))=-2`