How do you solve #4( p - 3) = 3( p + 5)#?

3 Answers
Aug 24, 2017

#p=27#

Refer to the explanation for the process.

Explanation:

Solve:

#4(p-3)=3(p+5)#

Expand using the distributive property: #a(b+c)=ac+bc#.

#4p-12=3p+15#

Add #12# to both sides.

#4p=3p+15+12#

Simplify.

#4p=3p+27#

Subtract #3p# from both sides.

#4p-3p=27#

Simplify.

#p=27#

Aug 24, 2017

#p=27#

Explanation:

#"distribute brackets on both sides of the equation"#

#rArr4p-12=3p+15#

#"collect terms in p to one side and numeric values on"#
#"the other side"#

#"subtract 3p from both sides"#

#4p-3p-12=cancel(3p)cancel(-3p)+15#

#rArrp-12=15#

#"add 12 to both sides"#

#pcancel(-12)cancel(+12)=15+12#

#rArrp=27#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left side "=(4xx24)=96#

#"right side "=(3xx32)=96#

#rArrp=27" is the solution"#

Aug 24, 2017

#p=27#

Explanation:

First multiply out the brackets:

#4p-12 = 3p+15#

Rearrange equation to have #p# on one side and numbers on the other:

#4p-3p=15+12#

Now solve the equation:

#p=27#