Question

What is the `"molarity"` of a `35.67*g` mass of calcium chloride dissolved in enough water to make a volume of 1.0*L?

Answer 1

We take the quotient, `"Molarity"="Moles of solute"/"Volume of solution"`

Explanation:

And thus........

`((35.67*g)/(110.98*g*mol^-1))/(1.0*L)=0.321*mol*L^-1` with respect to `"calcium chloride"`. What is the molar concentration with respect to chloride ion?