How do you use cross products to solve #4/p=14/28#?
1 Answer
Aug 25, 2017
Explanation:
#"using the method of "color(blue)"cross-products"#
#•color(white)(x)a/b=c/drArrad=bc#
#rArr4/p=14/28#
#rArr14p=4xx28#
#rArrp=(4xxcancel(28)^2)/cancel(14)^1==4xx2=8#
#color(blue)"As a check"# Substitute this value into the left side of the equation and if equal to the right side then it is the solution.
#"left side "=4/8=1/2#
#"right side "=14/28=1/2#
#rArrp=8" is the solution"#
