How do you solve #8m - 10= 5- 2m#?

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Answer 1 · 2017-08-27T19:09:21

See a solution process below:

First, add #color(red)(10)# and #color(blue)(2m)# to each side of the equation to isolate the #m# term while keeping the equation balanced:

#8m - 10 + color(red)(10) + color(blue)(2m) = 5 - 2m + color(red)(10) + color(blue)(2m)#

#8m + color(blue)(2m) - 10 + color(red)(10) = 5 + color(red)(10) - 2m + color(blue)(2m)#

#(8 + color(blue)(2))m - 0 = 15 - 0#

#10m = 15#

Now, divide each side of the equation by #color(red)(10)# to solve for #m# while keeping the equation balanced:

#(10m)/color(red)(10) = 15/color(red)(10)#

#(color(red)(cancel(color(black)(10)))m)/cancel(color(red)(10)) = (5 xx 3)/color(red)(5 xx 2)#

#m = (color(red)(cancel(color(black)(5))) xx 3)/color(red)(color(black)(cancel(color(red)(5))) xx 2)#

#m = 3/2#