Question

A triangle has corners at `(7 ,9 )`, `(4 ,1 )`, and `(3 ,8 )`. How far is the triangle's centroid from the origin?

Answer 1

The centroid is `7.6` unit far from origin.

Explanation:

Centroid `(x) = (x_1+x_2+x_3)/3 = (7+4+3)/3=14/3`

Centroid `(y) = (y_1+y_2+y_3)/3 = (9+1+8)/3=18/3 =6`

So centroid is at `(14/3 , 6)` and origin is `(0.0)`

Distance of centoid from origin is `d= sqrt((x_1-x_2)^2+(y_1-y_2)^2)`

or `d= sqrt( (14/3)^2+6^2) ~~ 7.6` unit

The centroid is `7.6` unit far from origin. [Ans]