Question

If the molar mass of a material is `147.01*g*mol^-1`, what mass of the material is required for a `1*L` volume of a `0.1*mol*L^-1` solution?

Answer 1

We use the definition of concentration......`"Concentration"="Moles"/"Volume"`.

And we get a required mass of `14.7*g`.

Explanation:

And thus `"moles"="volume"xx"concentration"`

We require.....`1*Lxx0.1*mol*L^-1=0.1*mol`.

And now we simply multiply this molar quantity by the molar mass, i.e. `0.1*molxx147.01*g*mol^-1=14.7*g`.....