Question #493df

1 Answer
JJ
Aug 31, 2017

#x=-1,-6#

Explanation:

Intercept form of a quadratic is #y=a(x-p)(x-q)#

There are two ways you can solve for the p and q are to use the quadratic formula or to factor the equation. Let's factor the equation.

We need #p+q=-7# and #p*q=6#. Let's find what two number have a product of 6: #(1 ,6)# or #(-1, -6)# or #(2,3)# or #(-2, -3)#

Using these pairs, let's find which pair gives a sum of -7.

#1+6=7#

#-1+ -6=-7#

#2+3=5#

#-2+ -3=-5#

It looks like the pair is #(-1,-6)#. You can plug either in for p or q. Now the equation #x^2-7x+6# becomes #(x+1)(x+6)#. If you were to set both equal to zero, you will end up with #(-1,0)# & #(-6,0)# as your zeros.

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