Question

How do you simplify `(- 2s ^ { 3} t ^ { 0} ) ^ { 5}`?

Answer 1

See a solution process below:

Explanation:

First, we can use these two rules of exponents to rewrite the term within the parenthesis:

`a = a^color(red)(1)` and `a^color(red)(0) = 1`

`(-2s^3t^color(red)(0))^5 => (-2^color(red)(1)s^3 1)^5 => (-2^color(red)(1)s^3)^5`

Now, use this rule for exponents to complete the simplification:

`(x^color(red)(a))^color(blue)(b) = x^(color(red)(a) xx color(blue)(b))`

`(-2^color(red)(1)s^color(red)(3))^color(blue)(5) => -2^(color(red)(1) xx color(blue)(5))s^(color(red)(3) xx color(blue)(5)) => -2^5s^15 => -32s^15`