How do you graph #8 + x/18 >= 7#?

1 Answer
Sep 2, 2017

See a solution process below:

Explanation:

First, we need to solve the inequality for #x#:

#-color(red)(8) + 8 + x/18 >= -color(red)(8) + 7#

#0 + x/18 >= -1#

#x/18 >= -1#

#color(red)(18) xx x/18 >= color(red)(18) xx -1#

#cancel(color(red)(18)) xx x/color(red)(cancel(color(black)(18))) >= -18#

#x >= -18#

To graph this we will draw a vertical line at #-18# on the horizontal axis.

The line will be a solid line because the inequality operator contains an "or equal to" clause.

We will shade to the right side of the line because the inequality operator also contains a "greater than" clause:

graph{x>=-18 [-30, 30, -15, 15]}