How do you solve #2( 2e - 8) + 5e = 29#?

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Answer 1 · 2017-09-03T00:12:41

#e = 5 #

First expand the brackets:

#2(2e-8) + 5e = 29#
#4e -16 +5e = 29#

Then collect all of the like terms together. In this case I add the e's together on the left hand side and add 16 to both sides.

#4e -16 +5e = 29#

#4e + 5e - 16 + 16 = 29 + 16#
#9e = 45#

Then solve for e by diving 45 by 9

#e = 45 / 9#
#e = 5#

Answer 2 · 2017-09-03T00:12:57

#e=5#

Refer to the explanation for the process.

Solve:

#2(2e-8)+5e=29#

Expand the left side.

#4e-16+5e=29#

Add #16# to both sides.

#4e+5e=29+16#

Simplify.

#9e=45#

Divide both sides by #9#.

#e=45/9#

Simplify.

#e=5#