First, expand the term in parenthesis by multiplying each term within the parenthesis by the term outside the parenthesis:
#2x + color(red)(5)(x + 3) = 120#
#2x + (color(red)(5) xx x) + (color(red)(5) xx 3) = 120#
#2x + 5x + 15 = 120#
Next, we can group like terms on the left side of the equation:
#(2 + 5)x + 15 = 120#
#7x + 15 = 120#
Then, subtract #color(red)(15)# from each side of the equation to isolate the #x# term while keeping the equation balanced:
#7x + 15 - color(red)(15) = 120 - color(red)(15)#
#7x + 0 = 105#
#7x = 105#
Now, divide each side of the equation by #color(red)(7)# to solve for #x# while keeping the equation balanced:
#(7x)/color(red)(7) = 105/color(red)(7)#
#(color(red)(cancel(color(black)(7)))x)/cancel(color(red)(7)) = 15#
#x = 15#