How do you solve #-17< 4- 3n \leq 15#?

1 Answer
Sep 4, 2017

See a solution process below:

Explanation:

First, subtract #color(red)(4)# from each segment of the system of inequalities to isolate the #n# term while keeping the system balanced:

#-17 - color(red)(4) < 4 - color(red)(4) - 3n <= 15 - color(red)(4)#

#-21 < 0 - 3n <= 11#

#-21 < -3n <= 11#

Now, divide each segment by #color(blue(-3)# to solve for #n# while keeping the segment balanced. However, because we are dividing or multiplying inequalities by a negative number we must reverse the inequality operators:

#(-21)/color(blue)(-3) color(red)(>) (-3n)/color(blue)(-3) color(red)(>=) 11/color(blue)(-3)#

#7 color(red)(>) (color(red)(cancel(color(black)(-3)))n)/cancel(color(blue)(-3)) color(red)(>=) -11/3#

#7 color(red)(>) n color(red)(>=) -11/3#

Or

#n >= -11/3# and #n < 7#

Or, in interval notation:

#[-11/3, 7)#