First, subtract #color(red)(4)# from each segment of the system of inequalities to isolate the #n# term while keeping the system balanced:
#-17 - color(red)(4) < 4 - color(red)(4) - 3n <= 15 - color(red)(4)#
#-21 < 0 - 3n <= 11#
#-21 < -3n <= 11#
Now, divide each segment by #color(blue(-3)# to solve for #n# while keeping the segment balanced. However, because we are dividing or multiplying inequalities by a negative number we must reverse the inequality operators:
#(-21)/color(blue)(-3) color(red)(>) (-3n)/color(blue)(-3) color(red)(>=) 11/color(blue)(-3)#
#7 color(red)(>) (color(red)(cancel(color(black)(-3)))n)/cancel(color(blue)(-3)) color(red)(>=) -11/3#
#7 color(red)(>) n color(red)(>=) -11/3#
Or
#n >= -11/3# and #n < 7#
Or, in interval notation:
#[-11/3, 7)#